4[x-2]=2[x-4]+2x

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Solution for 4[x-2]=2[x-4]+2x equation:


Simplifying
4[x + -2] = 2[x + -4] + 2x

Reorder the terms:
4[-2 + x] = 2[x + -4] + 2x
[-2 * 4 + x * 4] = 2[x + -4] + 2x
[-8 + 4x] = 2[x + -4] + 2x

Reorder the terms:
-8 + 4x = 2[-4 + x] + 2x
-8 + 4x = [-4 * 2 + x * 2] + 2x
-8 + 4x = [-8 + 2x] + 2x

Combine like terms: 2x + 2x = 4x
-8 + 4x = -8 + 4x

Add '8' to each side of the equation.
-8 + 8 + 4x = -8 + 8 + 4x

Combine like terms: -8 + 8 = 0
0 + 4x = -8 + 8 + 4x
4x = -8 + 8 + 4x

Combine like terms: -8 + 8 = 0
4x = 0 + 4x
4x = 4x

Add '-4x' to each side of the equation.
4x + -4x = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 4x + -4x

Combine like terms: 4x + -4x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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